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  • An electron collides with a hydrogen atom in its ground state and excites it to a state of . How

An electron collides with a hydrogen atom in its ground state and excites it to a state of \mathrm{n=3}. How much energy was given to the hydrogen atom in this inelastic collision?

Option: 1

\mathrm{13.6\ ev}


Option: 2

\mathrm{6.8\ ev}


Option: 3

\mathrm{12.1\ ev}


Option: 4

\mathrm{1.51\ ev}


Answers (1)

best_answer

\mathrm{\Delta E=E_f-E_i=E_i\left(\frac{1}{n_f^2}-\frac{1}{n_i^2}\right)}
\mathrm{n_i=1, n_f=3 \text { and } E_1=-13.6 \mathrm{eV}, so}
\mathrm{\Delta E=-13.6\left(\frac{1}{3^2}-\frac{1}{1^2}\right) \mathrm{ev} .}
\mathrm{\Delta E=12.1 \mathrm{ev}}

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