Get Answers to all your Questions

header-bg qa

An electron experiences no deflection if subjected to an electric field of 3.2\times10^5v/m and a magnetic induction of 2.0\times10^{-3}\tau. Both the fields are applied perpendicular to the path of electron and also to each other. If the electric field is removed then the electron will revolve in an orbit of radius

Option: 1

45m


Option: 2

4.5m


Option: 3

0.45m


Option: 4

0.46m


Answers (1)

best_answer

Initially we have

\mathrm{eV}_z \mathrm{eV_B}

V=\frac{E}{B}=\frac{3.2 \times 10^5}{2 \times 10^{-3}}=1.6 \times 10^8 \mathrm{~m} / \mathrm{s}

When electric field is removed, electron will only be moving in the influence of magnetic fields and it follows a circular motion with radius given as

\begin{aligned} r & =\frac{m V}{e B}=\frac{9.1 \times 10^{-31} \times 1.6 \times 10^8}{1.6 \times 10^{-19} \times 2 \times 10^{-3}} \\ & \Rightarrow \frac{9.1 \times 10^{-1}}{2}=0.45 \mathrm{~m} \end{aligned}

Posted by

Divya Prakash Singh

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks