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  • An electron moves in a circular orbit with a uniform speed  It produces a magnetic field <img alt="B" src="ht

An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. The radius of the circle is proportional to - 

Option: 1

\sqrt{\frac{B}{v}}


Option: 2

\frac{B}{v}


Option: 3

\sqrt{\frac{v}{B}}


Option: 4

\frac{v}{B}


Answers (1)

best_answer

Magnetic field produced by moving electron in circular path

B=\frac{\mu_{0 i}}{2 P}

Here, i=current, r=radius

But i=\frac{q}{T}=\frac{q}{2 \pi r} v\left[\because T=\frac{\text { Distarce }}{\text { velocity }}=\frac{2 \pi r}{v}\right]

Magnetic field at centre, B=\frac{u_0}{2 p} \times \frac{qv}{2 rp}

B=\frac{\mu_0 q v}{4 \pi r^2} \Rightarrow r \propto \sqrt{\frac{v}{B}} .

Posted by

Deependra Verma

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