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An electron revolves is a archie of radius 0.1 \dot{A} with a speed of 2.5 \times 10^5 \mathrm{~m} / \mathrm{sec} in Hydrogen atom. The magnetic field produced at the centre of the orbit due to the motion of the electron in tesla is

(\mu_0=4 \pi \times 10^{-7} \mathrm{H/m}, q_e=1.6 \times 10^{-19}c)

 

 

 

Option: 1

2T


Option: 2

3T


Option: 3

4T


Option: 4

5T


Answers (1)

best_answer

r=0.1 \dot{A}=0.1 \times 10^{-10} \mathrm{~m}

V=2.5 \times 10^5 \mathrm{~m} / \mathrm{sec}

So speed of electron in the orbit is

v=\frac{2 \pi r}{l}

time taken for one revolution

t=\frac{2 \pi r}{V}=\frac{2 \pi \times 0.1 \times 10^{-10}}{2.5 \times 10^5}=8 \pi \times 10^{-16} \mathrm{sec} \\

\text { Current } I=\frac{e}{t}=\frac{1.6 \times 10^{-19}}{8 \pi \times 10^{-16}}=\frac{0.2 \times 10^{-3}}{\pi}

                                                             =\frac{2}{\pi} \times 10^{-4} \mathrm{~A} \\

So B=\frac{\mu_0 I}{2r}= \frac{\left(4 \not \pi \times 10^{-7}\right) \times\left(\frac{2}{\not \pi} \times 10^{-4}\right)}{2 \times 0.1 \times 10^{-10}} \\

                          =\frac{8 \times 10^{-11}}{2 \times 10^{-11}}=4 \mathrm{~T}

Posted by

Deependra Verma

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