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An electrons enters between two horizontal plates separated by 2 \mathrm{~mm} and having a potential difference of  1000 \mathrm{~V}. The force on electron is -

Option: 1

8 \times 10^{-12} \mathrm{~N}


Option: 2

8 \times 10^{-14} \mathrm{~N}


Option: 3

8 \times 10^{9} \mathrm{~N}


Option: 4

8 \times 10^{14} \mathrm{~N}


Answers (1)

best_answer


Given,
\mathrm{ \begin{aligned} & \text { separation }(d)=2 \times 10^{-3} \mathrm{~m} \\ & \text { potential }(v)=1000 \mathrm{Volt} \end{aligned}}
To calculate force use -
\mathrm{ \begin{aligned} \bar{F} & =e \cdot \vec{E} \\ & =e \cdot \frac{V}{d} \quad \quad \quad \because E=\frac{v}{d} \\ & =1.6 \times 10^{-19} \times \frac{10^3}{2 \times 10^{-3}} \\ & =0.8 \times 10^{-13}=8 \times 10^{-14} \mathrm{~N} \end{aligned} }
 

Posted by

seema garhwal

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