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  • An EM wave of frequency  enters a dielectric medium of relative electric permittivi

An EM wave of frequency 3 \mathrm{~GHz} enters a dielectric medium of relative electric permittivity 2.25 from the vacuum. The wavelength of this wave in that medium will be

Option: 1

2.5 \mathrm{~cm}


Option: 2

3.6 \mathrm{~cm}


Option: 3

5.67 \mathrm{~cm}


Option: 4

6.67 \mathrm{~cm}


Answers (1)

best_answer

wavelength in vacuum \lambda=\frac{c}{f}=\frac{3 \times 10^8}{3 \times 10^9}
\lambda=0.1 \mathrm{~m}

\therefore \lambda in medium =\frac{0.1}{\mu}
where refractive index \mu=\sqrt{\mu_r \epsilon_r}
 Assume non magnetic material
\begin{gathered} \mu_r=1 \\ \Rightarrow \mu=\sqrt{2.25}=1.5 \\ \lambda_m=\frac{0.1}{15}=\frac{1}{15} \mathrm{~m}=6.67 \mathrm{~cm} . \end{gathered}

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avinash.dongre

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