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  • An excited hydrogen atom returns to the ground state. The wavelength of emitted photon is The principal quant

An excited hydrogen atom returns to the ground state. The wavelength of emitted photon is \lambda. The principal quantum number of the excited state will be
 

Option: 1

\mathrm{\left(\frac{\lambda R}{\lambda R-1}\right)^{1 / 2}}
 


Option: 2

\mathrm{\left(\frac{\lambda R-1}{\lambda R}\right)^{1 / 2}}
 


Option: 3

\mathrm{[\lambda R(\lambda R-1)]^{1 / 2}}
 


Option: 4

\mathrm{\left[\frac{1}{\lambda R(\lambda R-1)}\right]^{1 / 2}}


Answers (1)

best_answer

\mathrm{\frac{1}{\lambda} =R\left[\frac{1}{1}-\frac{1}{n^2}\right] }

\mathrm{\text { or } \frac{1}{n^2} =1-\frac{1}{\lambda R}=\frac{\lambda R-1}{\lambda R} }

\mathrm{\text { or } n =\sqrt{\frac{\lambda R}{\lambda R-1}} }
Hence option 1 is correct.
 

Posted by

himanshu.meshram

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