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An external battery charge a capacitor with resistance R in series. The given graph in which the dashed line shows the variation of \ln ^{I} with respect to the time the value of resistance is doubled. the new graph will be

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

best_answer

current in R C circuit is

I=I_{0} e^{-t / R C}

or.

\ln ^{I}=\ln ^{I_{0}}-\frac{t}{R \cdot C}

or

$$ \begin{aligned} & \ln ^{I}=\frac{-t}{R C}+\ln ^{I_{0}} \\ & \ln ^{I}=\frac{-t}{R C}+\ln ^{E_{0} / R} \end{aligned}

on comparing with eq. of straight line ie. y=m x+c. Intercept  =\ln ^{E_{0} / R}. and slope is \frac{-1}{R C}. As resistance increase, intercept decreases.

Posted by

seema garhwal

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