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  • An inductor coil stores 32 J of magnetic energy 7 dissipates energy as heat at the rate of 320 W when a current of 4A is passed through it. What is the time constant of the circuit when this coil i

An inductor coil stores 32 J of magnetic energy 7 dissipates energy as heat at the rate of 320 W when a current of 4A is passed through it. What is the time constant of the circuit when this coil is joined across an ideal battery.

Option: 1

0.1s


Option: 2

0.2s


Option: 3

0.3s


Option: 4

0.4s


Answers (1)

best_answer

\mathrm{\begin{aligned} U= \quad & \frac{1}{2} \mathrm{Li}^2 \\ & 32=\quad \frac{1}{2} \mathrm{~L}(4)^2 \\ \Rightarrow & \mathrm{L} \quad=4 \mathrm{H} \\ & \mathrm{P} \quad=\mathrm{i}^2 \mathrm{R} \\ & 320 \quad=(4)^2(\mathrm{R}) \\ \Rightarrow & \mathrm{R} \quad=20 \Omega \\ \therefore \quad \tau=\frac{\mathrm{L}}{\mathrm{R}} & =\frac{4}{20}=0.2 \mathrm{~s} . \end{aligned}}

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