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 An observer looks at a distant tree of height 10 m with a telescope of magnifying
  power of 20. To the observer the tree appears :
Option: 1

10 times nearer


Option: 2

20 times taller


Option: 3

20 times nearer


Option: 4

10 times taller


Answers (1)

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\\ \text{Magnification of a telescope is given by:} \\ M=\frac{\theta_{i}}{\theta_{o}}$ \\ $20=\frac{h / d_{i}}{h / d_{o}}$ \\ $20=\frac{d_{o}}{d_{i}}$ \\ Distance of image, $d_{i}=\frac{d_{o}}{20}$

Telescope resolves and brings the object closer which is far away from the telescope. Hence for telescope with magnifying power 20, the free appears 20 times nearer.

Posted by

manish painkra

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