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An X-ray tube with \mathrm{Cu} target is operated at 25 \mathrm{kV}. The glancing angle for a \mathrm{NaCl}. Crystal for the \mathrm{Cuk}_\alpha line is 15.8^{\circ}. Find the wavelength of this line. \mathrm{(\mathrm{d}\: for\: \mathrm{NaCl}=\left.2.82 \AA, \mathrm{h}=6.62 \times 10^{-27} \mathrm{erg}-\mathrm{sec}\right)}
 

Option: 1

\mathrm{3.06 \AA}


 


Option: 2

\mathrm{1.53 \AA}
 


Option: 3

\mathrm{\quad 0.75 \AA}
 


Option: 4

None of these


Answers (1)

best_answer

According to Bragg's law ,

\mathrm{\Rightarrow 2 \mathrm{~d} \sin \theta=\mathrm{n} \lambda }

\mathrm{ \mathrm{n}=1 \text { for first order } }

\mathrm{\Rightarrow 2 \times 2.82 \sin 15.8=\lambda }

\mathrm{\Rightarrow \lambda=5.64 \times 0.2723=1.53 \AA }

Hence option 2 is correct.





 

Posted by

avinash.dongre

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