Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Answer please! Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 second respectively. The molecular mass of A is 49u. Molecular mass of B will be

Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 second respectively. The molecular mass of A is 49u. Molecular mass of B will be

  • Option 1)

    50.00u

  • Option 2)

    12.25u

  • Option 3)

    6.50u

  • Option 4)

    25.00u

 

Answers (1)

best_answer

 

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

 

 As we know \frac{r_{A}}{r_{B}} =\frac{v/t_{A}}{V/t_{B}} =\sqrt{\frac{mB}{MA}}

=>\frac{10}{20}=\sqrt{\frac{M_{B}}{49}}

=>(\frac{1}{2})^{2}=\frac{MB}{49}

=>M_{B} =\frac{49}{4} =12.254


Option 1)

50.00u

This is incorrect answer

Option 2)

12.25u

This is correct answer

Option 3)

6.50u

This is incorrect answer

Option 4)

25.00u

This is incorrect answer

Posted by

perimeter

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2025 application correction facility from March 9 to 11
anam-khan

MBBS aspirants have 24 hours to fill NEET application form 2025; NTA sends multiple reminders
anam-khan

Reminder! NEET UG 2025 registration ends in two days; qualifying exam code

Latest Question