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  • Arrange the following metal ions in the order of increasing exchange energy: <img alt="\mathrm{Mn^{2+}, Cr^{2+}, Mn^{4+}, Sc^{2+}.}" src="/latex-image/?%5Cmathrm%7BMn%5E%7B2&plus;%7D%2C%20Cr%5E

Arrange the following metal ions in the order of increasing exchange energy: \mathrm{Mn^{2+}, Cr^{2+}, Mn^{4+}, Sc^{2+}.}

Option: 1

\mathrm{Sc^{2+}< Cr^{2+}<Mn^{4+}< Mn^{2+}}
 


Option: 2

\mathrm{Cr^{2+}< Mn^{4+}< Sc^{2+}< Mn^{2+} }
 


Option: 3

\mathrm{Sc^{2+}< Mn^{4+}< Cr^{2+}< Mn^{2+}}

 


Option: 4

\mathrm{Sc^{2+}<Mn^{2+}< Cr^{2+}< Mn^{4+}}


Answers (1)

best_answer

The number of unpaired electrons in  \mathrm{Sc^{2+}, Mn^{4+}, Cr^{2+},and \: Mn^{2+} }are 1, 3, 4, 5 respectively. The exchange energy increases as the number of unpaired electrons increases.

Hence option 3 is correct

 

Posted by

Deependra Verma

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