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  • At 100°C the vapour pressure of a solution of 6.5g of a solute in 100g water is 732 mm. If Kb=0.52, the boiling point of this solution will be:Opt

At 100°C the vapour pressure of a solution of 6.5g of a solute in 100g water is 732 mm. If Kb=0.52, the boiling point of this solution will be:

Option: 1

101°C


Option: 2

100°C


Option: 3

102°C


Option: 4

103°C


Answers (1)

best_answer

\\\frac{\mathrm{P}_{\mathrm{A}}^{\mathrm{o}}-\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{A}}}=\frac{\mathrm{m} \times \mathrm{M}_{\mathrm{A}}}{1000}\\\\\frac{760-732}{732}=\frac{\mathrm{m} \times 18}{1000}\\\\\begin{array}{l}{\mathrm{m}=2.125} \\\\ {\Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \mathrm{m}}\end{array}\\\\\begin{aligned} &=0.52 \times 2.125 \\ &=1.10 \\ \mathrm{T}_{\mathrm{s}} &=100+1.10 \\ &=101.1^{\circ} \mathrm{C} \end{aligned}

Therefore, Option(1) is correct.

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