Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • At the bottom of a tank having liquid with refractive index, 'm' is a plane mirror. A small object '  

At the bottom of a liquid tank with refractive index m. A plane mirror is placed at the bottom. An object is placed inside the liquid at a height h/2 above the mirror. Where will the image of the object appear to an observer looking from above?

Answers (1)

best_answer

Given- 

  • Refractive index of liquid = m
  • An object is placed at a height = h/2 above the mirror
  • The mirror is at the bottom of the tank
  • The observer is looking from above (in the air)

To find- The apparent position of the image as seen by the observer above the tank.

Solution- Firstly, a mirror forms a real image of the object, and as the object is at h/2 above the mirror, the real image will form at h/2 below the mirror. So, the distance of the image from the surface of the liquid = $$
(h -\frac {h}{2}) + \frac {h}{2} = h
$$

When light comes out of the liquid into the air, it appears to come from a shallower depth. So, $$
\text {Apparent depth} = \frac {\text {Real depth}} {\text {Refractive index}} = \frac {h}{m}
$$

Therefore, the image will appear at a depth of h/m from the surface of the liquid, as seen by the observer in air.

Posted by

Saniya Khatri

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

CM MK Stalin challenges union home minister Amit Shah on NEET, delimitation
anam-khan

Kota: NEET aspirant dies of heart attack; police recover prescriptions, medicines from room
anam-khan

Assam government proposes measures to ensure fair NEET exams amid malpractice concerns

Latest Question