Calculate the number of atoms of oxygen present in 88 g of CO2. What would be the mass (in gm) of CO having the same number of oxygen atoms?
112
116
110
120
LAWS OF CHEMICAL COMBINATIONS -
Law of Multiple Proportions :
This law was proposed by Dalton in 1803. According to this law, if two elements can combine to form more than one compound, the masses of one element that combine with a fixed mass of the other element, are in the ratio of small whole numbers.
-
No. of moles of CO2 = 88/(44 g/mol) = 2 moles
As one mole of CO2 contains two moles of oxygen atoms, so two moles of CO2 contain 4 moles of oxygen atoms.
Number of oxygen atoms = 4 X 6.023 X 1023 = 2.5092 X 1024
As 1 mole oxygen atoms present in 1 mole of CO so, 4 moles oxygen atoms are present in 4 moles of CO.
It’s mass is 4 X 28 = 112 g.