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Calculate the pressure exerted by 8.5gof ammonia (NH3) contained in a 0.5L vessel at 300K. For ammonia, a=4.0 atm L2mol-2, b=0.036 L mol-1

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\\\text{Number of moles of ammonia }\\\\ n=\frac{8.5}{17}=0.5 \mathrm{mol}$ \\\\ According to van der Waals equation\\ \\ $\left(P+\frac{a n^{2}}{V^{2}}\right)(V-n b)=n R T$\\\\ $P=\frac{n R T}{(V-n b)}-\frac{a n^{2}}{V^{2}}=\frac{0.5 \times 0.082 \times 300}{(0.5-0.5 \times 0.036)}-\frac{4(0.5)^{2}}{(0.5)^{2}}$ $=21.51 a t m$

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