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  • can be taken as the time taken for the concentration of a reactant

\mathrm{\frac{t_1}{5}} can be taken as the time taken for the concentration of a reactant to drop to \frac{9}{6} of its initial value. If the rate constant for a first order reaction is k, the \mathrm{\frac{t_{1}}{5}} can be written as

Option: 1

0.55/K


Option: 2

0.64/K


Option: 3

0.97/K


Option: 4

0.32/K


Answers (1)

best_answer

\mathrm{\begin{aligned} t_{1 / 5} & =\frac{2.303}{k} \log \frac{1 }{4/6} \\\\ & =\frac{2.303}{k} \log 9-\log 6 \\\\ & =\frac{2.303}{k}(2 \log 3-\log 6) \\\\ & =\frac{2.303}{k}(2 \times 0.47-0.7) \\\\ & =\frac{2.303}{k} \times 0.24 \\\\ & =\frac{0.55}{k} \end{aligned}}

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Pankaj

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