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  • Can someone help me with this, - Electrochemistry - NEET

When 0.1 mol \text{MnO}_{4}^{-2} is oxidised the quantity of electricity required to completely oxidise \text{MnO}_{4}^{-2} to \text{MnO}_{4}^{-} is :

  • Option 1)

    96500 C

  • Option 2)

    2 \times 96500 C

  • Option 3)

    9650 C

  • Option 4)

    96.50 C

 

Answers (1)

The oxidation reaction is 

MnO_{4}^{2-}\rightarrow MnO_{-}^{4}+e^{-}

+6                           +7             0.1mol

0.1mol

0.1 mol MnO_{4}^{2-} produces 0.1 mol of charge.

Q=0.1\times F=0.1\times 96500C=9650C\\


Option 1)

96500 C

This solution is incorrect 

Option 2)

2 \times 96500 C

This solution is incorrect 

Option 3)

9650 C

This solution is correct 

Option 4)

96.50 C

This solution is incorrect 

Posted by

Sabhrant Ambastha

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