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  • Can someone help me with this, - Laws of motion - NEET

Two stones of masses m and 2m are whirled in horizontal circles, the heavier one in radius \frac{r}{2} and the lighter one in radius r. The tangential speed of lighter stone is n times that of the  value of heavier stone when they experience same centripetal forces. The value of n is:

  • Option 1)

    3

  • Option 2)

    4

  • Option 3)

    1

  • Option 4)

    2

 

Answers (1)

best_answer

As we discussed in concept

Force in non-uniform Circular Motion -

F_{c}=ma_{c}=frac{mv^{2}}{r}

Ft = mat

F_{net}=msqrt{a_{c}^{2}+a_{t}^{2}}

m = mass

ac= centripetal acceleration

at = tangen tial acceleration

Fc = centripetal force

- wherein

overrightarrow{F_{c}}perpvec{v}

W is not equal to zero by tangential force.

W = 0 by centripetal force

 

 

 \frac{m_{1}v_{1}^{2}}{r}=\frac{mv_{2}^{2}}{(\frac{r}{2})}\:\:\:= V_{1}^{2}=4V_{2}^{2}

 

V_{1}=2V_{2}

i.e n=2

 


Option 1)

3

This option is incorrect.

Option 2)

4

This option is incorrect.

Option 3)

1

This option is incorrect.

Option 4)

2

This option is correct.

Posted by

Plabita

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