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The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance

  • Option 1)

    1.389 H

  • Option 2)

    138.88 H

  • Option 3)

    0.138 H

  • Option 4)

    13.89 H

 

Answers (1)

As we have learned @8482

v=1/2Li^{2}

L=\frac{2v}{i^{2}}=\frac{2\times 25\times 10^{-3}}{36\times 10^{-4}}=\frac{500}{36}H

L=13.89 H


Option 1)

1.389 H

Option 2)

138.88 H

Option 3)

0.138 H

Option 4)

13.89 H

Posted by

Vakul

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