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Compound X on reaction with \mathrm{O}_{3} followed by \mathrm{Zn} /$ $\mathrm{H}_{2} \mathrm{O} gives formaldehyde and 2-methyl propanal as products. The compound X is :
 

Option: 1

\mathrm{2-Methylbut-1-ene}
 


Option: 2

\mathrm{ 2-Methylbut-2-ene}
 


Option: 3

\mathrm{Pent-2-ene}
 


Option: 4

\mathrm{ 3-Methylbut-1-ene }


Answers (1)

best_answer

Given,

\therefore The alkene X is

It's IUPAC name is 3-Methylbut-1-ene

hence correct option is 4

Posted by

seema garhwal

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