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  • Confused! kindly explain, - Chemical Bonding and molecular structure - NEET

In which of the following molecules the central atom does not have sp^{3} hybridization?

  • Option 1)

    NH^{+}_{4}

  • Option 2)

    CH_{4}

  • Option 3)

    SF_{4}

  • Option 4)

    BF^{-}_{4}

 

Answers (1)

 

Determination of shape of molecules using VSEPR Theory -

calculate \:X

X=(No.\;of\:valence\:electrons\:of\:central\:atom\:)+(No.\:of\:other\:atom\:)+(Negative\:charge\:on\:the\:molecule)-(Positive\:charge\:on\:the\:molecule)

-

 

 We know that hybridization, H= \frac{1}{2}\left [ V+M-C+A \right ]

V= no of valence electrons in central atom

M = no of Surrounding monovalent atoms

C = Cationic charge

A = anionic charge

If SF_{4}\:,

V=6

M=4

C=A=0

it  =   \frac{1}{2}\left ( 6+4+0+0 \right )=5

\therefore SF_{4} is sp_{3}d hybridization and Not sp_{3}


Option 1)

NH^{+}_{4}

Correct

Option 2)

CH_{4}

Incorrect

Option 3)

SF_{4}

Incorrect

Option 4)

BF^{-}_{4}

Incorrect

Posted by

Vakul

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