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  • Confused! kindly explain, - Thermodynamics - NEET

During an isothermal expansion, a confined ideal gas does -150 J of work against its surroundings. This implies that:

  • Option 1)

    150 J heat has been removed from the gas

  • Option 2)

    300 J of heat has been added to the gas

  • Option 3)

    No heat is transferred because the process is isothermal 

  • Option 4)

    150 J of heat has been added to the gas

 

Answers (1)

best_answer

Using

First law in Isothermal Process -

Delta Q= Delta U+Delta W
 

- wherein

Isothermal process

Delta T= 0

Delta U= 0

Heat supplied is equal to work done.

 

 Negative work done by gas implies work is done on the system.

Q = \Delta U+W \ \ \ -(i)

For isothermal process, \Delta U =0

\therefore Q= W =-150\ T

Hence, heat is given to the system.


Option 1)

150 J heat has been removed from the gas

This option is incorrect

Option 2)

300 J of heat has been added to the gas

This option is incorrect

Option 3)

No heat is transferred because the process is isothermal 

This option is incorrect

Option 4)

150 J of heat has been added to the gas

This option is correct

Posted by

Aadil

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