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  • Consider a reaction that follows the rate law . If the conce

Consider a reaction that follows the rate law \mathrm{R=K[A]^{3 / 2}}. If the concentration of \mathrm{A} is increased by \mathrm{100 \%}  by what percentage does the rate of the reaction change?

Option: 1

100 \%


Option: 2

200 \%


Option: 3

300 \%


Option: 4

400 \%


Answers (1)

best_answer

\mathrm{R=k(A)^{3 / 2}}
If \mathrm{A\rightarrow 2A}

\mathrm{ R^{\prime}=K[2 A ]^{3 / 2}=2^{3 / 2}\, \mathrm{K[A]}}
\mathrm{ R^{\prime}=2.82 \, \mathrm{R}}

\mathrm{ R^{\prime}} is increased by \mathrm{ 282 \%} i.e a \mathrm{ 300 \%}

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