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Consider an endothermic reaction $X\rightarrow Y$ with the activation energies $E_{b}\: and\: E_{f}$ for the backward and forward reactions, respectively. In general
Option: 1
$E_{b}\: < \: E_{f}$

Option: 2
$E_{b}\: > \: E_{f}$

Option: 3
$E_{b}\: =\: E_{f}$

Option: 4
There is no definite relation between $E_{b}\: and\: E_{f}$

Answers (1)

best_answer

For endothermic reaction,

$\Delta H=+ve$

$\Delta H=E_{f}-E_{b},it\; means\; E_{b}< E_{f}$

Posted by

SANGALDEEP SINGH

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