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  • Consider an transistor amplifier in common-emitter configuration. The current gain of the transis

Consider an \mathrm{NPN} transistor amplifier in common-emitter configuration. The current gain of the transistor is \mathrm{100}. If the collector current changes by \mathrm{1\ mA}, what will be the change in emitter current

Option: 1

\mathrm{1.1\ mA}


Option: 2

\mathrm{1.01\ mA}


Option: 3

\mathrm{0.01\ mA}


Option: 4

\mathrm{10\ mA}


Answers (1)

best_answer

\mathrm{Current\ gain\ \beta=\frac{\Delta i_c}{\Delta i_b} \Rightarrow \Delta_b=\frac{1 \times 10^{-3}}{100}=10^{-5} \mathrm{~A}=0.01 \mathrm{~mA}}\\ \mathrm{By\ using\ \Delta i_e=\Delta i_b+\Delta i_c \Rightarrow \Delta i_e=0.01+1=1.01 \mathrm{~mA}}

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