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  • Determine the enthalpy of reaction (in kJ) for the following: <img alt="H_2 (g) + \frac{1}{2}O_2(g)\rightarrow H_2O(g)" src="http://entrancecorner.oncodecogs.com/gif.latex?H_2%20%28g%29%20a

Determine the enthalpy of reaction (in kJ) for the following:
H_2 (g) + \frac{1}{2}O_2(g)\rightarrow H_2O(g)

Using the following bond enthalpies (in kJ/mol): H-H (432); O=O(496); H-O (463)

Option: 1

246


Option: 2

-246


Option: 3

1606


Option: 4

-1606


Answers (1)

best_answer

\\\Delta H = \Sigma E_{\textup{reactant bonds broken}} - \Sigma E_{\textup{product bonds broken}} \\\Delta H = [432 + (0.5)(496)] - [(2)(463)] \\\Delta H = 680 - 926 \\\Delta H = - 246kJ

There are 2 O-H bonds hence we have multiplied 2 to O-H bond enthalpy and similarly we multiplied \frac{1}{2} to O-O bond enthalpy

 

Posted by

Pankaj Sanodiya

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