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Deuteron and alpha particle in air are at separation 1\AA. The magnitude of electirc field intensity on \alpha- particle due to deutron is - 

Option: 1

5.76\times 10^{11}N/c


Option: 2

1.44\times 10^{11} N/C


Option: 3

2.4\times 10^{11}N/C


Option: 4

None


Answers (1)

best_answer

F=\frac{Kq_{1}q_{2}}{r^{2}}
Electric field , 
E=\frac{Kq_{1}}{r^{2}} =\frac{9\times10^{9}\times1.6\times10^{-19}}{10^{-10}\times10^{-10}}      
=14.4\times10^{-10}\times10^{20}

=14.4\times10^{11}N/c

Posted by

chirag

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