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Diamond has face-centred cubic lattice. There are two atoms at \left ( 0,0,0 \right ) and \left ( \frac{1}{4},\frac{1}{4},\frac{1}{4} \right )coordinates. The ratio of other carbon-carbon bond distance to the edge of the unit cell is  \sqrt{\frac{x}{16}} , then what is x?

(Response should be in integer only lke 78).

Option: 1

3


Option: 2

1


Option: 3

4


Option: 4

7


Answers (1)

best_answer

A distance formula needs to use for 3d-

d_{c-c}=\sqrt{\frac{1}{16}+\frac{1}{16}+\frac{1}{16}}=\sqrt{\frac{3}{16}}  

x = 3

Posted by

Rakesh

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