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  • Dioxygen can be prepared by:Option: 1 Heating <img alt="\mathrm{KClO}_{3}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BKClO%7D_%

Dioxygen can be prepared by:

Option: 1

Heating \mathrm{KClO}_{3}


Option: 2

Thermal decomposition of oxides like \mathrm{Ag}_{2} \mathrm{O}, \mathrm{Pb}_{3} \mathrm{O}_{4} etc.


Option: 3

Electrolysis of water


Option: 4

All of these


Answers (1)

2 \mathrm{KClO}_3 \xrightarrow[\mathrm{MnO}_2]{\Delta} 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{~Pb}_3 \mathrm{O}_4(\mathrm{s}) \longrightarrow 6 \mathrm{PbO}(\mathrm{s})+\mathrm{O}_2(\mathrm{g})

On electrolysis of \mathrm{H}_{2} \mathrm{O}, \mathrm{O}_{2} is obtained at anode.

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Kshitij

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