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  • Ed wavelength emitted by an atom m of atomic number z=11 is \lambda. The atom number for an atom that emits <img alt="\mathrm{k_\alpha}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmath

Ed wavelength emitted by an atom m of atomic number z=11 is \lambda. The atom number for an atom that emits \mathrm{k_\alpha} radiation with wave length 4 \lambda.
 

Option: 1

z=6


Option: 2

z=4


Option: 3

z=11


Option: 4

z=44


Answers (1)

best_answer

\begin{aligned} &\mathrm{ \frac{1}{\lambda} \propto(z-1)^2 }\\ &\mathrm{ \frac{\lambda_1}{\lambda_2}=\left(\frac{z_2-1}{z_1-1}\right)^2}\\ &\mathrm{ \frac{1}{4}=\left(\frac{z_2-1}{11-1}\right)^2 }\\ &\mathrm{ \left(\frac{1}{4}\right)^{1 / 2}=\frac{z_2-1}{11-1} }\\ &\mathrm{ \frac{1}{2}=\frac{z_2-1}{10} \Rightarrow 5=z_2-1 }\\ &\mathrm{ z_2=6}\\ \end{aligned}

Posted by

Suraj Bhandari

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