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  • Energy released in fusion of 1 kg of deuterium nucleiOption: 1 <img alt="9 \times 10^{13} \mathrm{~J}" src="/latex-image/?9%20%5Ctimes%2010%5E%7B13%7

Energy released in fusion of 1 kg of deuterium nuclei

Option: 1

9 \times 10^{13} \mathrm{~J}


Option: 2

6 \times 10^{27} \mathrm{~J}


Option: 3

2 \times 10^7 \mathrm{KwH}


Option: 4

8 \times 10^{23} \mathrm{MeV}


Answers (1)

best_answer

Fusion reaction of deuterium

{ }_1 \mathrm{H}^2+{ }_1 \mathrm{H}^2 \rightarrow{ }_2 \mathrm{He}^3+{ }_0n{ }{ }^1+3.27 \mathrm{MeV}

E=\frac{6.02 \times 10^{23} \times 10^3 \times 3.27 \times 1.6 \times 10^{-13}}{2 \times 2}

\Rightarrow \mathrm{E} \approx 9 \times 10^{13} \mathrm{~J}

Posted by

Suraj Bhandari

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