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  • Equivalent amounts of both the gases hydrogen and oxygen are put in a container with a pinhole that allows both gases to escape. In the time it takes for one-fourth of a mole of hydrogen to escape,

Equivalent amounts of both the gases hydrogen and oxygen are put in a container with a pinhole that allows both gases to escape. In the time it takes for one-fourth of a mole of hydrogen to escape, how many moles of oxygen gas escape?

Option: 1

\frac{1}{16}


Option: 2

\frac{1}{8}


Option: 3

\frac{1}{4}


Option: 4

\frac{2}{3}


Answers (1)

Let's use Graham’s Law

\\\frac{nO_2}{nH_2}=\frac{\sqrt{mH_2}}{\sqrt{mO_2}}\\ \\\frac{nO_2}{0.25}=\frac{\sqrt 2}{\sqrt{32}}\\ \\nO_2=\frac{0.25}{4}\\ \\nO_2=\frac{1}{16}

Posted by

Sumit Saini

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