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  • Exchange energy for <img alt="\mathrm{Cr^{2+}}" src="/latex-image/?%5Cmathrm%7BCr%5E%7B2&pl

Exchange energy for \mathrm{Cr^{2+}} ion is (When K= energy per pair of parallel spins)

Option: 1

6K


Option: 2

4K


Option: 3

8K


Option: 4

10K


Answers (1)

best_answer

Exchange energy \mathrm{= n(n-1)K/2} where \mathrm{n=} number of electrons in parallel spins. For \mathrm{Cr^{2+}, n=4} so, Exchange energy = 6K

Hence option 1 is correct.

Posted by

SANGALDEEP SINGH

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