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  • Find the surface energy (in Joule) of water kept in a cylindrical vessel of radius 6cm. surface tension of water =<img alt="75\times 10^{-3}Nm^{-1}" src="/latex-image/?75%5Ctimes%2010%5E%7B-3%7DNm%

Find the surface energy (in Joule) of water kept in a cylindrical vessel of radius 6cm. surface tension of water =75\times 10^{-3}Nm^{-1}

Option: 1 0.0017

Option: 2 0.00085

Option: 3 0.00042

Option: 4 0.085

Answers (1)

best_answer

As we learned 

 

Definition of Surface Tension -

W=T\Delta A

If \ \Delta A=1,then\ T=W

- wherein

T\rightarrow Surface \: tension

W\rightarrow work \: done

 

 Surface \: energy=TA

=\frac{22}{7}\times (6\times 10^{-2})^{2}\times 75\times 10^{-3}J

=8.5\times 10^{-4}J

 

Posted by

Anam Khan

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