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  • For a cell reaction involving a two­ electron change, the standard e.m.f. of the cell is found to be 0.295 V at 25<img alt="^{\circ}C" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cdpi

For a cell reaction involving a two­ electron change, the standard e.m.f. of the cell is found to be 0.295 V at 25^{\circ}C. The equilibrium constant of the reaction at 25^{\circ}C  will be

Option: 1

1 \times 10^{-10}


Option: 2

29.5 \times 10^{-2}


Option: 3

10


Option: 4

1 \times 10^{10}


Answers (1)

best_answer

E^{\circ}_{cell}=\frac{0.0591}{n}logK_{c}

0.295=\frac{0.0591}{2}logK_{c}

or\; \; \; 0.295=0.0295\, logK_{c}

or\; \; \; K_{c}=antilog\; 10\; \; or\; K_{c}=1\times 10^{10}

Therefore,option(4) is correct

Posted by

Ritika Jonwal

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