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  • For a given first order reaction, the reactant reduces to 1 / 4 th its initial value in 10 minutes. The rate constant of the reaction and time required 20% reduces is:  <d

For a given first order reaction, the reactant reduces to 1 / 4 th its initial value in 10 minutes. The rate constant of the reaction and time required 20% reduces is:
 

Option: 1

0.1386 \mathrm{~min}-1,1.6 \mathrm{~min}


Option: 2

0.0693 \mathrm{~min}-1,2 \mathrm{~min}


Option: 3

0.1386 \mathrm{~mol} \mathrm{~L}-1 \mathrm{~min}-1,2.6 \mathrm{~min}


Option: 4

0.0693 \mathrm{~mol} \mathrm{~L}-1 \mathrm{~min}, 3 \mathrm{~min}


Answers (1)

best_answer

\begin{aligned} \\& \mathrm{t=\frac{2.303}{k} \log \left\{\frac{A_0}{A_0-x}\right\}} \\ \\& \mathrm{k=\frac{2.303}{10} \log \left\{\frac{100}{25}\right\}} \\ \\& \mathrm{k=\frac{2.303}{10} \log \{4\}} \end{aligned}

\begin{aligned} & \mathrm{t=\frac{2.303}{k} \log \left\{\frac{A_0}{A_0-x}\right\} }\\ \\&\mathrm{ t=\frac{2.303}{0.1386} \log \left\{\frac{100}{80}\right\}} \\ \\& \mathrm{ t=1.6 \mathrm{~min}} \end{aligned}

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