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  • For a reaction  the observed rate law <img alt="\mathr

For a reaction \mathrm{A+B\rightarrow P} the observed rate law \mathrm{rate=K\left [ A \right ]^{2}\left [ B \right ]} if concentration \mathrm{\left [ A \right ]} is in excess then rate law become ;-

\mathrm{rate=K'\left [ B \right ]} the correct relationship b/w \mathrm{K\: and\: K'} is

 

Option: 1

\mathrm{k^{\prime}=k^{1 / 2}}
 


Option: 2

\mathrm{k^{\prime}=k^{1 / 4}}
 


Option: 3

\mathrm{k^{\prime}=k[A]^2}
 


Option: 4

None of these.


Answers (1)

best_answer

It is based on ostwald isolation method.

This method is based on the fact that concentration terms of reactants except one. If present in Excess remains Virtually unchange thus can be Merged with the rate constant.

In this lase the rate of reaction depends only on the concentration of \mathrm{B} reactant Which is not present in excess.    

Hence option 3 is correct

Posted by

seema garhwal

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