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  • For a rocket propulsion velocity of exhaust gases relative to rocket is  <img alt="2 \mathrm{~km} / \mathrm{s}" src="https://entrancecorner.oncodecogs.com/gif.latex?2%20%5Cmathrm%7B%7Ekm%

For a rocket propulsion velocity of exhaust gases relative to rocket is  2 \mathrm{~km} / \mathrm{s}  If mass of rocket system is  1000 \mathrm{~kg}  The rate of fuel consumption for a rocket to rise up with an acceleration  4.9 \mathrm{~m} / \mathrm{s}^2  will be -

Option: 1

12.25 \mathrm{~kg} / \mathrm{s}


Option: 2

7.35 \mathrm{~kg} / \mathrm{s}


Option: 3

17 \mathrm{~kg} / \mathrm{s}


Option: 4

5.2 \mathrm{~kg} / \mathrm{s}


Answers (1)

best_answer

\mathrm{F_{\text {net }} =m a \\ }                                                           \mathrm{F=V \frac{d M}{d t}}   .....(1)

\mathrm{F-m g =m a }  ....(2)                                          \mathrm{F=2000 \times \frac{d M}{d t}}   .....(3)

 

 

Now, from equation - (2)
\mathrm{ F-1000 \times 10=1000 \times 4.9 }


\mathrm{ F \approx 15000 \mathrm{~N} }


put the value of \mathrm{ F } in equation (3) we get


\mathrm{ 15000 =2000 \times \frac{d M}{d t}}  

\mathrm{ 7.5 =\frac{d M}{d t} \quad} .

Posted by

chirag

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