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  • For a transistor, the current amplification factor is . The transistor is connected in common emitter configuration. The c

For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration. The charge in the collector current when the base current changes by \mathrm{6\ mA} is

Option: 1

\mathrm{6\ mA}


Option: 2

\mathrm{4.8\ mA}


Option: 3

\mathrm{24\ mA}


Option: 4

\mathrm{8\ mA}


Answers (1)

best_answer

\begin{aligned} &\mathrm{ \alpha=0.8 \Rightarrow \beta=\frac{0.8}{(1-0.8)}=4} \\ &\mathrm{ \text { Also } \beta=\frac{\Delta i_c}{\Delta i_b} \Rightarrow \Delta i_c=\beta \times \Delta i_b=4 \times 6=24 \mathrm{~mA}} \end{aligned}

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