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  • For <img alt="\mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}+\mathrm{D}, \Delta \mathrm{H}=-50 \mathrm{~kJ\; mole} { }^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BA%7D&

For \mathrm{A}+\mathrm{B} \rightarrow \mathrm{C}+\mathrm{D}, \Delta \mathrm{H}=-50 \mathrm{~kJ\; mole} { }^{-1}. The activation energy for the forward reaction is 115 kJ. Then the activation energy for the backward reaction is

Option: 1

165 kJ


Option: 2

105 kJ


Option: 3

85 kJ


Option: 4

40 kJ


Answers (1)

best_answer

The activation en orgy for the back wand resection is equal to the sum of the activation energy of the forward 8 enthaleby change of the \mathrm{x^n}
 

\mathrm{\left(E_a\right)_{\text {back }}=115-(-50)=165 \mathrm{~kJ}}

Posted by

Devendra Khairwa

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