Get Answers to all your Questions

header-bg qa

Four identical metal plates placed parallel with equal separation between consecutive plates. plates A and D are connected to a cell. What will happen, if plates B and C are connected by a conducting wire?

Option: 1

\text { charge become }\left(\frac{C V}{2}\right)


Option: 2

\text { charge become }\left({2C V}\right)


Option: 3

\mathrm{change{\, \, in \, \, \, charge\, \, become\, \, \left(\frac{C V}{6}\right)}


Option: 4

\mathrm{change{\, \, in \, \, \, charge\, \, become\, \, \left(\frac{C V}{3}\right)}


Answers (1)

best_answer

Potential, \mathrm{V_A>V_B>V_C>V_D }
when B is connected
to \mathrm{ C, V_B=v_c } and no
electric field remains in
between Initially there are capacitors (each of C ) are in series, so \mathrm{ q_i=\frac{c}{3} v }
After connecting B and C, there remains two capacitors so \mathrm{ q_f=\frac{c}{2} v }
thoufire,\mathrm{ \Delta q=q_f-q_i=\frac{C V}{2}-\frac{C V}{3}=\frac{C V}{6} Ans }
 

Posted by

seema garhwal

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks