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  • Four resistance network shown in figure, Choose the correct options.

Four resistance network shown in figure, Choose the correct options.

Option: 1

Current through BC is zero.


Option: 2

Current I is 3A.


Option: 3

Reffective i.e. R_A_F=6\Omega


Option: 4

Current through AB and AC is equal.


Answers (1)

best_answer

Since the upper arm resistance and lower arm resistance are in same ratio

\frac{{R_1}}{{R_6}}=\frac{3}{6}, \quad \frac{R_2}{R_5}=\frac{3}{6}, \frac{R_3}{R_4}=\frac{3}{6}. ie. \frac{R_1}{R_0}=\frac{R_2}{R_5}=\frac{R_3}{R_4},

Hence, Current through BC and DE  is zero.

\begin{aligned} & R_A=R_1+R_2+R_3=(3+3+3) \Omega=9 \Omega \\ & R_B=R_4+R_5+R_6=(6+6+6) \Omega=18 \Omega \\ & \frac{1}{R_{\text {eff }}}=\frac{1}{R_A}+\frac{1}{R_B}=\frac{1}{9}+\frac{1}{18}=\frac{2+1}{18}=\frac{3}{18} \\ & R_{\text {eff }}=\frac{18}{3}=6 \Omega \end{aligned}

Hence, from ohm's law, current I is I=\frac{V}{R}=\frac{12}{6}=2 \mathrm{~A}

Current through AB and AC is not equal as resistance is unequal.

Posted by

SANGALDEEP SINGH

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