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  •  Given that <img alt="\mathrm{Fa}_{\mathrm{A}}>\mathrm{Ea}^{\prime}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BFa%7D_%7B%5Cmathrm%7BA%7D%7D%3E%5Cmathrm%7BEa%7D%5E%7B%

 Given that \mathrm{Fa}_{\mathrm{A}}>\mathrm{Ea}^{\prime} for two reactions. If the Temperature of the reacting systems is increased from \mathrm{T_1 to T_2}. The choose the correct option from the following [note.. K ' is rate constant at higher temperature 3 .
 

Option: 1

\frac{k_1^{\prime}}{k_1}=\frac{k_2^{\prime}}{k_2}


Option: 2

\frac{k_1^{\prime}}{k_1}<\frac{k_2}{k_2}


Option: 3

\frac{k_1^{\prime}}{k_1}>\frac{k_2^{\prime}}{k_2}


Option: 4

\frac{k_1^{\prime}}{k_1}>\frac{2 k_2^{\prime}}{k_2}


Answers (1)

A\c to Arrhenius for two reaction
\mathrm{\begin{aligned} & \log \left(\frac{k_2}{k_1}\right)=\frac{E_a}{k}\left[\frac{T_2-T_1}{T_1 T_2}\right] \\ & \log \left(\frac{k_{\prime}^{\prime}}{k_i^{\prime}}\right)=\frac{E_a^{\prime}}{R} \cdot\left[\frac{T_2-T_1}{T_2 T_1}\right] \end{aligned} }
from eq \mathrm{,(1)+(2) }
\mathrm{k_2 / k_1 \propto E_a \& k_2^{\prime} / k_1^{\prime} \propto E_a^{\prime} }
\mathrm{since \mathrm{F}_a>\mathrm{E}_a{ }^{\prime} \therefore \frac{k_2}{k_1}>\frac{k_\alpha^{\prime}}{k_1^{\prime}} \Rightarrow \frac{k_1^{\prime}}{k_1}>\frac{k_\alpha{ }^{\prime}}{k_1} }
 

Posted by

Sumit Saini

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