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  • Help me please, - Alcohols, Phenols and Ethers - NEET

Consider the following reaction,

ethanol\overset{PBr_{3}}{\rightarrow}X\overset{alc.KOH}{\rightarrow}Y

\xrightarrow[(ii)H_{2}O,\:heat)]{(i)\:H_{2}SO_{4}\:room\:temperature}\:Z

the product Z is:

  • Option 1)

    CH_{3}CH_{2}-O-CH_{2}-CH_{3}

  • Option 2)

    CH_{3}-CH_{2}-O-SO_{3}H

  • Option 3)

    CH_{3}CH_{2}OH

  • Option 4)

    CH_{2}=CH_{2}

 

Answers (1)

best_answer

As we learnt in

Alcohols reaction with phosphorus trihalides -

Form alkyl halides 

- wherein

ROH+PX_{3}\rightarrow RX+H_{3}PO_{3}

X = Cl, Br, I

 

 

Alcohol formation by hydration of alkenes -

Follow electrophilic addition mechanism (Markownikoff)

- wherein

RCH\equiv CH_{2} + H_{2}O \overset{H_{2}SO_{4}}{\rightarrow} RCH(OH)CH_{3}

 

 

 

CH_{3}CH_{2}OH\xrightarrow[]{}{PBr_{3}}CH_{3}CH_{2}Br \xrightarrow[] {}{alc.koH}CH_{2}=CH_{2}\xrightarrow[]{H_{2}SO_{4},\ H_{2}O,\ \Delta}CH_{3}-CH_{2}OH


Option 1)

CH_{3}CH_{2}-O-CH_{2}-CH_{3}

This is incorrect option

Option 2)

CH_{3}-CH_{2}-O-SO_{3}H

This is incorrect option

Option 3)

CH_{3}CH_{2}OH

This is correct option

Option 4)

CH_{2}=CH_{2}

This is incorrect option

Posted by

divya.saini

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