Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Help me solve this Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules

Which one of the following orders is correct for the bond dissociation enthalpy of halogen molecules 

  • Option 1)

    I2 > Br2 > Cl2 > F2

  • Option 2)

    Cl2 > Br2 > F2 > I2

  • Option 3)

    Br2 > I2 > F2 > Cl2

  • Option 4)

    F2 > Cl2 > Br2 > I2

 

Answers (1)

 

Bond strength -

The energy required to break one mole of bonds of particular type in gaseous state is called bond energy or bond strength.

- wherein

The same amount of energy is released in formation of one mol of particular bond.

 

 Bond dissociation enthalpies of halogen family decreased down the group as the size of atom increases. The bond dissociation enthalpy of fluorine, is however, lower than those of cheorine and bromine because of inter electronic repusion present in small atoms of flourine.

Hence order of bond dissociation enthalpies for halogen is

cl_{2> }Br_{2}> F_{2}> I_{2}


Option 1)

I2 > Br2 > Cl2 > F2

This is incorrect option

Option 2)

Cl2 > Br2 > F2 > I2

This is correct option

Option 3)

Br2 > I2 > F2 > Cl2

This is incorrect option

Option 4)

F2 > Cl2 > Br2 > I2

This is incorrect option

Posted by

Vakul

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NTA Overhaul: 1,000 secure exam centres, biometrics to prevent fraud, question paper changes, suggests panel
anam-khan

NEET syllabus 2025 out; NMC uploads subject-wise topics
anam-khan

What changes in NEET UG? Experts’ panel suggests multi-stage exam, security overhaul, simpler process to NTA

Latest Question