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  • Help me understand! - Laws of motion - NEET

A block of mass m is placed on a smooth inclined wedge ABC of inclination \Theta  as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and \Theta for the block to remain stationary on the wedge is

  • Option 1)

    a = g cos \Theta

  • Option 2)

    a = \frac{g}{sin \Theta }

  • Option 3)

    a = \frac{g}{cosec \Theta }

  • Option 4)

    a = g tan \Theta

 

Answers (3)

As we have learned

Equilibrium of Concurrent Forces -

If all the forces working on a body are acting on the same point then they are said to be concurrent.

- wherein

sum vec{F_{net}}= 0   

or sum vec{F_{x}}= 0,sum vec F_{y}= 0, sum vec F_{z}= 0

 

ast  Three forces will be in equilibrium if they are represented by three sides of triangle taken in order

 

 

 

For Block to be stationary net force along the plane =0

\Rightarrow mg\sin \theta =ma\cos \theta \Rightarrow a=g\tan \theta

 

 

 

 

 

 


Option 1)

a = g cos \Theta

This is incorrect

Option 2)

a = \frac{g}{sin \Theta }

This is incorrect

Option 3)

a = \frac{g}{cosec \Theta }

This is incorrect

Option 4)

a = g tan \Theta

This is correct

Posted by

subam

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4) a =gtan

Posted by

Viswamanikandan

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4

Posted by

Viswamanikandan

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