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  • if debrohlie wavelength of electron and photon are equal

If debroglie wavelength of electron and photon are equal then prove that total energy of electron is greater than energy of photon? Explain in detail

Answers (1)

energy of photon=\frac{hc}{\lambda_p}

{\lambda_e}=\frac{h}{mv}

{m}=\frac{h}{\lambda_e v}

there for energy of electron

{E_e}=\frac{1}{2}\frac{h}{\lambda_e v}v^2=\frac{hv}{2\lambda_e}

\frac{E_p}{E_e}=\frac{2C}{ v}

since C>>>v

Ep>Ev

Posted by

Safeer PP

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