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  • If    for the reaction, <img alt="3Na + Au^3^+ \rightarrow 3Na^{+}+Au" src="https:

If \Delta G^0   for the reaction, 3Na + Au^3^+ \rightarrow 3Na^{+}+Au   is 1220 kj , then find E_{cell}^{0}

Option: 1

4.2


Option: 2

4.5


Option: 3

4.8


Option: 4

5.1


Answers (1)

best_answer

\Delta G^0 =- nFE^0

\mathrm{1220 kJ = -3 \times 96487 \times E^0}

E_{cell}^{0}= 4.21\approx 4.2

 

Posted by

Sanket Gandhi

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